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Mathematics
use logarithmic differentiation to find y=x^(x+2)
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\[\ln(y)=\ln(x^{x+2}) =>\ln(y)=(x+2)\ln(x)\]
take derivative of both sides
\[\frac{y'}{y}=(1+0)\ln(x)+(x+2)\frac{1}{x}\]
now multiply both sides by y
\[y'=y[\ln(x)+\frac{x+2}{x}]=x^{x+2}[\ln(x)+\frac{x+2}{x}] \]
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