Ask your own question, for FREE!
Mathematics 36 Online
OpenStudy (anonymous):

Vector problem, I have to draw it though...

OpenStudy (anonymous):

|dw:1314315711313:dw|

OpenStudy (anonymous):

a = <2,pi/3> b = <3,3pi/4> c= <1,pi/6> Write down a,b,c in terms of i and j Get a +c in terms of i and j

OpenStudy (anonymous):

This is similar to a recent question, the notation is <magnitude, angle>

OpenStudy (amistre64):

\[a+c = <2+1,\frac{(2)pi}{(2)3}+\frac{pi}{6}>\] \[a+c = <3,\frac{3pi}{6}>\] \[a+c = 3i+\frac{pi}{2}j\]

OpenStudy (amistre64):

<xpart, ypart> is vector notation

OpenStudy (amistre64):

vector equivalent of polar cordinates ; now theres something to write home about :)

OpenStudy (amistre64):

x = r cos(t) ; y = r sin(t)

OpenStudy (amistre64):

r is given and t is givne

OpenStudy (amistre64):

\[a+c=<1,\sqrt{3}>+<\frac{1}{2},\frac{1}{\sqrt{3}}>\] \[a+c=<1+\frac{1}{2},\sqrt{3}+\frac{1}{\sqrt{3}}>\] \[a+c=(1+\frac{1}{2})i +(\sqrt{3}+\frac{1}{\sqrt{3}})j\]

OpenStudy (anonymous):

a= i + sqrt3 j

OpenStudy (amistre64):

right

OpenStudy (amistre64):

i forgot the middle of the question :)

OpenStudy (anonymous):

b = -3/sqrt2i +3/sqrt2j

OpenStudy (anonymous):

c= sqrt3/2i + 1/2j

OpenStudy (amistre64):

c = cos(30)i + sin(30)j

OpenStudy (amistre64):

|dw:1314316788946:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Lilmunchin: Trump or Biden
4 minutes ago 65 Replies 2 Medals
ARTSMART: Art!
1 hour ago 5 Replies 5 Medals
Jasonisyours: What were the key causes of the French Revolution in 1789?
1 hour ago 3 Replies 5 Medals
PureSoulless: Why is the word "Pedophile" always censored in yt vids?
1 day ago 3 Replies 0 Medals
Jalli: What's 58x3634u00b07
23 hours ago 6 Replies 3 Medals
arriya: who wanna play roblox
1 day ago 5 Replies 1 Medal
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!