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the shortest side of a triangle is 7 inches shorter than the longest side. The middle side is twice as long as the short side. Find the length of all three sides if the perimeter is 31 inches.
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short side= x-7 mid= 2(x-7) long=x. (x-7)+2(x-7)+x=31. x-7+2x-14+x=31. 4x-21=31. 4x=52. x=13.
Let a = length of long side and b = length of short side. c= lenght of remaining side. The following relationships are given. b=a-7 c=2b a+b+c = 31 inches. a+(a-7)+2(a-7)=31 a+a-7+2a-14=31 4a=31+7+14=52 a=13 b=6 c=12
Long side= 13 in. short side= 6 in. middle side = 12. 13+6+12=31
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