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OpenStudy (anonymous):

find intervals where f(x)= lnx/x is increasing and decreasing.

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OpenStudy (anonymous):

f'(x)= (1 - lnx)/x^2

OpenStudy (anonymous):

x> 1 inicreasing x<1 decreaseing is this?

OpenStudy (anonymous):

i need to know how to find the answer

OpenStudy (anonymous):

f(x) = (ln (x))/x df(x)/dx = (x(1/x) +1(lnx))/x^2

OpenStudy (anonymous):

\[\prime(x)=(1+\ln x)/x^2\]

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OpenStudy (anonymous):

and then i m confused lol

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