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OpenStudy (anonymous):
find intervals where f(x)= lnx/x is increasing and decreasing.
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OpenStudy (anonymous):
f'(x)= (1 - lnx)/x^2
OpenStudy (anonymous):
x> 1 inicreasing x<1 decreaseing is this?
OpenStudy (anonymous):
i need to know how to find the answer
OpenStudy (anonymous):
f(x) = (ln (x))/x df(x)/dx = (x(1/x) +1(lnx))/x^2
OpenStudy (anonymous):
\[\prime(x)=(1+\ln x)/x^2\]
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OpenStudy (anonymous):
and then i m confused lol
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