Question

Verify the function and state its domain. Indicate which theorems you are using, and which functions you are assuming to be continuous:

1/(sqrt{x+2})

Answer 1

Will the domain be (0, infinity) ?

Answer 2

x+2>0 x>-2
????

Answer 3

\[\sqrt{x+2}\] it is the denominator, which means that it can not be 0.
and \[\sqrt{x+2}\]means X+2>=0
so x+2>0
so X >-2

Answer 4

Okay, how do I prove it is continuous?