Question

4x^2-x-3=0
solve by completing the square
x= ??

Answer 1

x=-0.75

Answer 2

4x2 - x - 3 = 0 ⇒ x=1 , x=-0.75

Answer 3

\[4x^2-x-3=4\left(x-\frac{1}{8}\right)^{2}-\frac{49}{16}\]

Answer 4

4x^2-x-3=0


4(x^2-x/4-3/4)=0


4(x^2-x/4+1/16-1/16-3/4)=0


4((x-1/8)^2-1/64-3/4)=0


4((x-1/8)^2-49/64)=0


4(x-1/8)^2-4(49/64)=0


4(x-1/8)^2-49/16=0


4(x-1/8)^2=49/16


(x-1/8)^2=49/64


x-1/8 = sqrt(49/64) or x-1/8=-sqrt(49/64)


x-1/8 = 7/8 or x-1/8 = -7/8


x = 7/8+1/8 or x = -7/8+1/8


x = 8/8 or x = -6/8


x = 1 or x = -3/4


Answers are \[\large x=1 \textrm{ or } x=-\frac{3}{4}\]

Answer 5

jim, you are good!!!