Mathematics OpenStudy (anonymous):

4x^2-x-3=0 solve by completing the square x= ?? OpenStudy (anonymous):

x=-0.75 OpenStudy (anonymous):

4x2 - x - 3 = 0 ⇒ x=1 , x=-0.75 OpenStudy (zarkon):

$4x^2-x-3=4\left(x-\frac{1}{8}\right)^{2}-\frac{49}{16}$ jimthompson5910 (jim_thompson5910):

4x^2-x-3=0 4(x^2-x/4-3/4)=0 4(x^2-x/4+1/16-1/16-3/4)=0 4((x-1/8)^2-1/64-3/4)=0 4((x-1/8)^2-49/64)=0 4(x-1/8)^2-4(49/64)=0 4(x-1/8)^2-49/16=0 4(x-1/8)^2=49/16 (x-1/8)^2=49/64 x-1/8 = sqrt(49/64) or x-1/8=-sqrt(49/64) x-1/8 = 7/8 or x-1/8 = -7/8 x = 7/8+1/8 or x = -7/8+1/8 x = 8/8 or x = -6/8 x = 1 or x = -3/4 Answers are $\large x=1 \textrm{ or } x=-\frac{3}{4}$ OpenStudy (anonymous):

jim, you are good!!!

Latest Questions solodive: Idk I'm just curious this isn't for class or anything but how do you take care of
13 minutes ago 2 Replies 0 Medals purplecow: The graph shows the functions f(x) PX Angie X pate what is the solution to the pair of equations represented by PX and GX Papi write any two solutions for G
3 hours ago 2 Replies 0 Medals BrokenAngel07: I wrote this some time ago, idk of it'd be considered a song or something I wrote.
4 hours ago 4 Replies 1 Medal Olive2006: Tell me what you think of my story. https://www.wattpad.com/1255046896-unruly-hea
4 hours ago 7 Replies 3 Medals chocalatechipcookie: @vocaloid In circle A, marc BC is 67u00b0 and marc EF is 74u00b0: What is mu2220F
3 hours ago 2 Replies 0 Medals Glyzdl: Question: Given a 60-u00b5C point charge located at the origin, find the total el
17 hours ago 0 Replies 0 Medals Glyzdl: 4) A point charge of 3 nC is located at the point (1, 1, 1) in free space. What c
17 hours ago 0 Replies 0 Medals Sailor: So. I'm gonna send out another plea for help, and I'm desperate at this point. I need to know what I did wrong here.
20 hours ago 7 Replies 3 Medals link1234: what yall think? aye aye aye juice is in wooden box i thought u were gonna shot em first its a different story when ur poppin the percs my demons beatin me
19 hours ago 9 Replies 2 Medals Sailor: Could I get help on this? I know that absolute value should be "6th grade knowledge" but this is Algebra 2 we're talking about.
1 day ago 1 Reply 1 Medal