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ah Volume of pyramid is \(\frac{1}{3}\times h \times s^2 \)
Now all we have to do is to convert h into terms of \(\alpha\) and s
\[tan (\alpha) = \frac{h}{\frac{s}{2}}\]
\[h = \frac{tan(\alpha)\times s}{2}\] \[Volume = \frac{s^3 \times tan(\alpha)}{6}\]
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