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OpenStudy (anonymous):
think itd be b=2A/h
OpenStudy (anonymous):
\[b = \frac{2A}{h}\]
OpenStudy (anonymous):
how do you work it out?
OpenStudy (anonymous):
first of all u want to get b alone right? so to get ride of the 1/2, multiply both sides by reciprocal which is 2.so 2A=bh and to get rid of the h youd divide both sides by h.so 2A/h=b
OpenStudy (anonymous):
how do you work it out?
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
duz it help?
OpenStudy (anonymous):
so basically to undo multiplication u divide. to undo division u multiply. the only way to move a fraction to the other side would be to multiply by the reciprocal. for ex if 1/3x=6 multiply by 3/1 to get x=18
OpenStudy (anonymous):
ohhh
OpenStudy (anonymous):
is it helpful
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OpenStudy (anonymous):
but if you had 1/2 bh over 2 it would get id of 1/2 but wouldnt it affect the bh?
OpenStudy (anonymous):
ur right
OpenStudy (anonymous):
so..
OpenStudy (anonymous):
no it wouldnt, only if you did 1/2 over 2 if you left the bh alone.
OpenStudy (anonymous):
wouldnt affect bh everything cancels xcept the bh
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OpenStudy (anonymous):
yea, thanks,
OpenStudy (anonymous):
no prblm
OpenStudy (anonymous):
A=1/2bh
OpenStudy (anonymous):
A over 2 = 2A
OpenStudy (anonymous):
1/2 bh over 2 =bh
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OpenStudy (anonymous):
wait a sec what do u mean by A over 2 is 2A
OpenStudy (anonymous):
so its b= 2A over h
OpenStudy (anonymous):
i got it right?
OpenStudy (anonymous):
wait u lost me. what r u trying to do
OpenStudy (anonymous):
2A over h stays 2a over h, then bh over h becomes b
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OpenStudy (anonymous):
r u trying 2 solve 4 b
OpenStudy (anonymous):
yep
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
ok so it is b=2A over h
OpenStudy (anonymous):
yea
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OpenStudy (anonymous):
dont let the letters in the equation confuse u think of it as a regular equation with regular #