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OpenStudy (anonymous):

think itd be b=2A/h

OpenStudy (anonymous):

\[b = \frac{2A}{h}\]

OpenStudy (anonymous):

how do you work it out?

OpenStudy (anonymous):

first of all u want to get b alone right? so to get ride of the 1/2, multiply both sides by reciprocal which is 2.so 2A=bh and to get rid of the h youd divide both sides by h.so 2A/h=b

OpenStudy (anonymous):

how do you work it out?

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OpenStudy (anonymous):

?

OpenStudy (anonymous):

duz it help?

OpenStudy (anonymous):

so basically to undo multiplication u divide. to undo division u multiply. the only way to move a fraction to the other side would be to multiply by the reciprocal. for ex if 1/3x=6 multiply by 3/1 to get x=18

OpenStudy (anonymous):

ohhh

OpenStudy (anonymous):

is it helpful

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OpenStudy (anonymous):

but if you had 1/2 bh over 2 it would get id of 1/2 but wouldnt it affect the bh?

OpenStudy (anonymous):

ur right

OpenStudy (anonymous):

so..

OpenStudy (anonymous):

no it wouldnt, only if you did 1/2 over 2 if you left the bh alone.

OpenStudy (anonymous):

wouldnt affect bh everything cancels xcept the bh

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OpenStudy (anonymous):

yea, thanks,

OpenStudy (anonymous):

no prblm

OpenStudy (anonymous):

A=1/2bh

OpenStudy (anonymous):

A over 2 = 2A

OpenStudy (anonymous):

1/2 bh over 2 =bh

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OpenStudy (anonymous):

wait a sec what do u mean by A over 2 is 2A

OpenStudy (anonymous):

so its b= 2A over h

OpenStudy (anonymous):

i got it right?

OpenStudy (anonymous):

wait u lost me. what r u trying to do

OpenStudy (anonymous):

2A over h stays 2a over h, then bh over h becomes b

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OpenStudy (anonymous):

r u trying 2 solve 4 b

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

ok so it is b=2A over h

OpenStudy (anonymous):

yea

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OpenStudy (anonymous):

dont let the letters in the equation confuse u think of it as a regular equation with regular #