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Find the quotient of quantity of18 a squared b plus 12 a b cubed minus 24 a b all over 6 a b. 3a + 2b2 − 4 3ab + 2ab2 − 4 3a2b + 2ab3 − 4ab 3a3b2 + 2a2b4 − 4a2b2
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\[\frac{18a^2b+12ab^3-24ab}{6ab}\]
factor a \[6ab\] from the numerator to write \[6ab(3a+2b^2-4)\] then cancel so second term is the answer
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