Question

Find the quotient of quantity of18 a squared b plus 12 a b cubed minus 24 a b all over 6 a b.

3a + 2b2 − 4

3ab + 2ab2 − 4

3a2b + 2ab3 − 4ab

3a3b2 + 2a2b4 − 4a2b2

Answer 1

\[\frac{18a^2b+12ab^3-24ab}{6ab}\]

Answer 2

factor a
\[6ab\] from the numerator to write
\[6ab(3a+2b^2-4)\] then cancel so second term is the answer