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How do I factor this: 16k²-1
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(4k + 1) (4k - 1)
Hav u tried to solve?
saifoo, stop trying to make people learn, jeez :p
\[x^2-y^2=(x+y)(x-y)\]
LOl, the accounts of both asker's and answer's can get banned due to that.
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This is marked as Cheating.
yes i agree
\[16k²-1\] just try it first , bbut i am giving u solution . \[(4k)^2-(1)^2\] as we know that \[a^2-b^2=(a+b)(a-b)\] hence here \[(4k)^2-(1)^2=(4k+1)(4k-1)\]
thank you, I wasn't sure how to factor this specific equation and I was just stumped
no problem
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difference of squares
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