Question

-56y^7 divided by -7y^5= 8y^2, right?

Answer 1

yea u r right

Answer 2

Indeed.

Answer 3

since :
\[-56y^7/-7y^5 = 8y^7/y^5\]
as we know that \[a^b/a^c=a^{(b-c)}\]
now
\[8y^7/y^5=8y^{(6-5)}\]
that is
\[8y^2\]

Answer 4

got it