Find end behaviors and horizontal asymptotes if any: f(x) = (2x+1)/ (x^2-2x+1) Please explain. Thank you~

No horizontal asymptotes. Since the 'x' degree in the denominator is greater than the numerator, y=0.

y=o is the end behavior? Can you explain why?

y=0 is the horizontal asymptote. And the reason why is explained above.

Oh.. I thought that was the explanation for why there are no horizontal asymptotes.. so why are there no horizontal asymptotes? For the same reason?

Oh wait, y=0 is a horizontal asymptote. Lost my train of thought lol. Sorry mate. That is the one.

It is zero because the denominator is getting larger faster than the numerator. At infinity, a large number over a very much bigger large number will converge to zero. Zero is the horiz asymptote

Okay, Lol then how do I find the model of the end behavior?

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