Find end behaviors and horizontal asymptotes if any:
f(x) = (2x+1)/ (x^2-2x+1) Please explain. Thank you~

Question

anonymous · Answer

No horizontal asymptotes. Since the 'x' degree in the denominator is greater than the numerator, y=0.

anonymous · Answer

y=o is the end behavior? Can you explain why?

anonymous · Answer

y=0 is the horizontal asymptote. And the reason why is explained above.

anonymous · Answer

Oh.. I thought that was the explanation for why there are no horizontal asymptotes.. so why are there no horizontal asymptotes? For the same reason?

anonymous · Answer

Oh wait, y=0 is a horizontal asymptote. Lost my train of thought lol. Sorry mate. That is the one.

anonymous · Answer

It is zero because the denominator is getting larger faster than the numerator.  At infinity, a large number over a very much bigger large number will converge to zero.  Zero is the horiz asymptote

anonymous · Answer

Okay, Lol then how do I find the model of the end behavior?