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Mathematics

OpenStudy (anonymous):

how do you factor: 4v²-33v+8?

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OpenStudy (saifoo.khan):

(v-8) (4 v-1)

OpenStudy (aroub):

(4v-1)(v-8)

OpenStudy (aroub):

wow!

OpenStudy (anonymous):

how do you get that though?

OpenStudy (anonymous):

4x8=32. So you need two numbers that multiply to 32 and add up to -33. Those two are -32 and -1.

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OpenStudy (saifoo.khan):

OpenStudy (anonymous):

Then plug them in.... and you get... 4v^2-32v-v+8... Take common... 4v(v-8)-1(v-8) then you get... (4v-1)(v-8)

jimthompson5910 (jim_thompson5910):

Answer is (v-8)(4v-1) See the attached image for how I got that answer.

OpenStudy (anonymous):

ok... so now I have 4v²+15-4. 4X4 is 16...and I'm not seeing a way to factor that out.

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OpenStudy (anonymous):

how do you get that though?

jimthompson5910 (jim_thompson5910):

I'm not sure what you're referring to

jimthompson5910 (jim_thompson5910):

oh this is a new problem?

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