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Two boats traveling the same direction leave a harbor at noon. After 2 hr, they are 40 miles apart. If one boat travels twice as fast as the other, find the rate of each boat
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20 mi/hr and 40 mi/hr
\[2y-2x=40\]\[y=2x\]Solve the equations
Distance = (rate)(time)
y = 10
xy=-10
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x=1/2y
no... u can check my answer by analyzing the problem. After traveling for 2 hrs, they are 40 mi apart. \[40 X 2 = 80\]\[20 x 2 = 40. \]\[80-40=40\]\[Then 40 is twice of 20.\]
for the slowest car 20 yes I get it now
boat 2(r-40) =4(r+40)
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