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Solve for x. (4^-2)(4^x+1)(4^3)=(4^5)
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\[\frac{1}{16} \times (4^x+1) = \frac{4^5}{4^3}\]
\[\frac{1}{16} \times (4^x+1) = 4^2\]
\[4^x+1 = 16 \times 16\]
\[4^x = 155.\]
\[x = \log_{4}155\]\[x = 3.638\]
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I can't believe i did that.
LOL.
It looks scary.
Thank you! I didn't even know how to start it haha
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