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If G(x) = 3x + 1, then G-1(1) is
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\[1=3x+1\] \[0=3x\] \[x=0\]
so \[G(0)=1\] and \[G^{-1}(1)=0\]
can it be 1/3
no assuming what you mean is \[G^{-1}(x)\] in inverse function
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