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OpenStudy (anonymous):

If G(x) = 3x + 1, then G-1(1) is

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OpenStudy (anonymous):

\[1=3x+1\] \[0=3x\] \[x=0\]

OpenStudy (anonymous):

so \[G(0)=1\] and \[G^{-1}(1)=0\]

OpenStudy (anonymous):

can it be 1/3

OpenStudy (anonymous):

no assuming what you mean is \[G^{-1}(x)\] in inverse function

OpenStudy (anonymous):

Thanks!

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OpenStudy (anonymous):

yw

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