Question

how do you find the sum of the series \[\sqrt{2}+1, 1, \sqrt{2}-1 +...\infty\] ?

Answer 1

You cannot find the sum. It will go to -infinity. As the terms are not bounded the series diverges.

Answer 2

I cannot even tell what is the next term...

Answer 3

It's written there a "+"

Answer 4

You are right, I thought it is -1 each term

Answer 5

I have the solution, had a bath and cleared my mind :-)

this is a geometric series with ratio \[\ 1/(sqrt{2} +1)\]
s=\[\sqrt{2}+1\]
So the infinite sum is = (sqrt{2}+1)*1/(1- 1/(sqrt2+1))

Answer 6

4.1213

Answer 7

THANK GOD U EXIST!!

Answer 8

Is it clear? The way I wrote it is not that nice, some of the formulas are not showing properly

Answer 9

yeah, i guess so, thanx ：）