Question

How do you write the equation of the line passing through the points (3,-4) and (2,6)?

Answer 1

finding gradient m=-10
y=mx+c
taking any points eg (3,-4)
-4=-10(3)+c
c=28

therefore

y=-10x +28

Answer 2

formula for gradient
m=(y2-y1)/(x2-x1)

taake the given points and substitude them on the equation

Answer 3

How did you get 28?

Answer 4

plz giv medal

Answer 5

y=-10x+c
sub the give points
-4=-10(3)+c
c=26 sorry for that of 28

Answer 6

sorry.made a mistake
y=m(x1-x2)+y2
6=m(2-3)-4
10=2m-3m
10=-m
m=-10


y=mx+c
6=(-10)2+c
6=-20+c
c=26


y=mx+c
y=-10x+26