Mathematics 69 Online
OpenStudy (anonymous):

x+2squarerootx-3=0. solve for x?

OpenStudy (anonymous):

$x+2\sqrt{x}-3=0$ $2\sqrt{x}=3-x$ square to get $4x=(3-x)^2$ $4x=9-6x+x^2$ $x^2-10x+9=0$ solve for x get $(x-1)(x-10)=0$ $x=1$ or $x=10$ butyou are not done here because you have to check your answers.

OpenStudy (anonymous):

ok that was way wrong $x^2-10x+9=0$ $(x-1)(x-9)=0$ $x=1$ or $x=9$ now it is right

OpenStudy (anonymous):

now check because there is no guarantee they work $1+2\sqrt{1}-3=0$ $1+2-3=0$ that one works $9+2\sqrt{9}-3=0$ $9+3-3=0$ that one does not work. only solution is $x=1$

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