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what are the x and y intercepts for(x^2+y^2-8x)^2=64x^2+64y^2?
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for the x intercept make y 0 for the y intercept make x 0
If I did my work right I think x=0 and y=4
Hmm...don't think so, there's a square in there...
i just keep getting 0 and thats wrong so i dont know what to do
Yeah I'm checking my work
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y= plus minus 8 on setting x = 0
and y = 0.
0 and 16 for x so it has to be (16,0) (0,0) (0,8) (0,8)
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