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f(x)=1-6x solve f(x)=0
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plug in o for x. so 1-6(0)=1
f(x)=1-6x 0=1-6x -1=-6x -1/(-6)=x 1/6=x x=1/6 So the solution is \[\large x=\frac{1}{6}\]
but its a function in terms of x
exactly, but they want to know which values of x make f(x) equal to zero not f(0)
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oh i see
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