IF a car leaves at 3pm traveling at 80 mph and another car leaves 2 hrs later at 100 mph. What equation would you use to know what time the the second car would catch up with the first?

Question

anonymous · Answer

First Car
equation (x is time after second car started)
           First Car=      80x+2*80

Second Car=100x

anonymous · Answer

$$100*t\text{ = }160+80* t$$

anonymous · Answer

why 160?

anonymous · Answer

t = 8 hours, 5pm+8 = 1am the next day.

anonymous · Answer

because first car stared 160 miles ahead

anonymous · Answer

r t = d, The 80mph car has traveled 80*2 miles before the 100mph car begins to move.