Question

IF a car leaves at 3pm traveling at 80 mph and another car leaves 2 hrs later at 100 mph. What equation would you use to know what time the the second car would catch up with the first?

Answer 1

First Car
equation (x is time after second car started)
First Car= 80x+2*80

Second Car=100x

Answer 2

\[100*t\text{ = }160+80* t\]

Answer 3

why 160?

Answer 4

t = 8 hours, 5pm+8 = 1am the next day.

Answer 5

because first car stared 160 miles ahead

Answer 6

r t = d, The 80mph car has traveled 80*2 miles before the 100mph car begins to move.