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For the following function, find the vertex, the axis of symmetry, and the x- and y-intercepts of the graph. f(x)=x^2-10x
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vertex is \[-\frac{b}{2a}=\frac{10}{2}=5\] for the first coordinate second coordinate is -25 , what you get when you replace x by -5
hold on, I'm confused. I thought I needed an ordered pair for the vertex..
and i made a mistake. axis of symmetry is x - 5 vertex is (5,-25)
x = 5
Ohhhhh.... duh, I'm low on sleep. sry
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wow rita, very nice! you guys are awesome.
I posted another like this if you guys are able to take a look.
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