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solve for x: 4^(3x+8)=12 please show steps
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step one take the log \[(3x+8)\ln(4)=\ln(12)\] step two distribute \[3\ln(4)x+8\ln(4)=\ln(12)\] subtract \[3\ln(4)x=\ln(12)-8\ln(4)\] divide \[x=\frac{\ln(12)-8\ln(4)}{3\ln(4)}\]
loved your work in "it takes a thief"!
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