Question

Give exact and approximate solutions to three decimal places.

(x+7)^2=36

Answer 1

take square root of both sides

then subtract 7 on both sides

Answer 2

and don't forget to write both
\[x+7=6\] or
\[x+7=-6\]

Answer 3

id +- a sqrt(36) then subtract out a 7

Answer 4

that's easy for you to say

Answer 5

\[(\pm \sqrt{36}-7+7)^2 = 36\]