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Mathematics 23 Online
OpenStudy (anonymous):

y^2+27x+9y+3xy

OpenStudy (anonymous):

3x(y+9) y(y+9) so finally (3x+y)(y+9) basically factor by grouping

OpenStudy (anonymous):

multiply it out 2 ensure its correct if u want to check the ans

OpenStudy (anonymous):

Thank you

OpenStudy (anonymous):

aha want to help me out with others

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

what other qs do u have

OpenStudy (anonymous):

6z^2+24z-az-4a

OpenStudy (anonymous):

ur still gonna use factoring by grouping. so 6z(z+4) -a(z+4) finally (6z-a)(z+4)

OpenStudy (anonymous):

makes sense?

OpenStudy (anonymous):

no lol what about 24x^3-21x^2+8x-7 ima ask you the ones i skipped

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

im here

OpenStudy (anonymous):

factor by grouping. 8x(3x^2+1) -7(3x^2+1) so (8x-7)(3x^2+1)

OpenStudy (anonymous):

anything else ??

OpenStudy (anonymous):

yes whats the factor of v^2+5v+4

OpenStudy (anonymous):

(v+1)(v+4) v=-1 and -4

OpenStudy (anonymous):

other q's ??

OpenStudy (anonymous):

a^2+5a+6

OpenStudy (anonymous):

(a+2)(a+3) so then its a=-2 and -3

OpenStudy (anonymous):

b^2+5b-14

OpenStudy (anonymous):

(b+7)(b-2) b= -7 and 2

OpenStudy (anonymous):

r^2+4r-21

OpenStudy (anonymous):

r^2+4r-21

OpenStudy (anonymous):

20x^3-16x^2+4x

OpenStudy (anonymous):

can you break it down for me please

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