Question

a car traveling at +7.0 m/s accelerates at a rate of +0.80 m/s^2 for an interval of 2.0 s. findddd vf...

Answer 1

vf=vi+at=7.0m/s+2s(0.80m/s^2)=8.6m/s

Answer 2

\[v=u +at\]
v= final velocity
u= initial velocity
a= acceleration
t= time

Answer 3

y=u+at,
7+(0.80*2)
7+1.6=8.6.
u=initial velocity.
v=final velocity.
a=accelaration