Question

What is the domain and range of:
1) sqrt of x^2 -4
2) sqrt of 4-x2

Answer 1

\[x^2 - 4 \ge 0 \]
\[x\ge 2\]

Answer 2

\[4 -x^2 \ge 0 \]
\[ 2\ge x\]

Answer 3

how about teh ranges

Answer 4

how come for 4-x^2, teh domain isn't all real numbers?

Answer 5

because its in a square root xD

Answer 6

range
y^2 = x^2 - 4
(sqrt(y^2 + 4)) = x all real numbers


y^2 = 4 -x^2
x = sqrt(4 -y^2)
\[4 - y^2 \ge 0 \]
\[ 2\ge y \]

Answer 7

thanks Mim_x3 ah I feel so honored she replied to one of my questions ..

Answer 8

LOL, sorry for interrupting in you answering the question
Mimi*

Answer 9

No it's an honor

Answer 10

LOL

Answer 11

i know this sounds dumb but if it write taht \[y \ge 2\]
is taht teh same thing as what u wrote: \[2 \ge y\]

Answer 12

i mean y is less tahn 2

Answer 13

\[y \le 2 \]

Answer 14

no it isn't first is y is always greater than 2 second is y is less than 2

Answer 15

lols , no you only write y is less then 2 when its a minus xD

Answer 16

Thank you both! =)

Answer 17

yw (: