Question

Simpligy by removing factors of 1.
1280v^10y^4
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100v^8y^2
simplified form is = ?

Answer 1

First, reduce 1280 over 100 to get 128/10 = 64/5


Now subtract corresponding exponents: So for v it's 10-8= 2 and for y it's 4-2 = 2. These values will be the final exponents for the corresponding variables.


This means that the final answer is \[\large \frac{64v^2y^2}{5}\]

Answer 2

Thank you so much