Just started coursework and stuck on first exercise. "Positive root of the following equation: 34*x^2+68*x-510". I figured out that I can assign a number to X but is there a way to assign an open variable to X in order to run the equation (e.g. x = ?)?

Question

Just started coursework and stuck on first exercise. "Positive root of the following equation: 34*x^2+68*x-510".  I figured out that I can assign a number to X but is there a way to assign an open variable to X in order to run the equation (e.g. x = ?)?

anonymous · Answer

I have no idea what you are talking about
I just started, so if you figure this out you might be able to help me

anonymous · Answer

which problem set are you referring to?

anonymous · Answer

Based strictly on your question, I think you are asking for an input for x? Basically, x=print("Give x a value:").

anonymous · Answer

He's referring to the 'Introduction to Python' handout that has a few problems in Python for you just to get you started using the language.

anonymous · Answer

um... are you sure your doing 6.00? the first pset is merely asking for input and printing it back out

anonymous · Answer

http://ocw.mit.edu/courses/electrical-engineering-and-computer-science/6-00-introduction-to-computer-science-and-programming-fall-2008/assignments/getting_started.pdf this one

anonymous · Answer

seriously, you shouldn't worry yourself over that problem. IT DOESNT MATTER!!!!!!!!! get on with the lectures and psets and you will learn everything you need to know in due time.

anonymous · Answer

import math

print "a*x^2 + b*x + c = 0"
a = float(raw_input("a = "))
b = float(raw_input("b = "))
c = float(raw_input("c = "))
x1 = ((-b + math.sqrt(b*b - 4*a*c))/(2*a))
x2 = ((-b - math.sqrt(b*b - 4*a*c))/(2*a))
print "x1 =", x1
print "x2 =", x2

Run as a module

anonymous · Answer

its simple...we know that roots of a equation can be found as [-b +or- sqrt(b^2 -4*ac)]/2ac.......solving which we get the roots as 3 and -5......simple...so i guess ur root must be 3.