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Solve system using substitution 3x+y=5 2x-5y=9
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just for linear practice :) 3x+y=5 2x-5y=9 x = (9+25)/(2+15) y = (27-10)/(-15-2) maybe?
solve for one variable first: i'm going to use the first equation: 3x+y=5 so y=-3x+5 plug that in to equation 2 2x-5(-3x+5)=9 2x+15x-25=9 17x-25=9 17x=34 x=2 plug that in: 3(2)+y=5 6+y=5 y= -1 so if all is correct, x=2, y=-1
trying to do a determinant backwards is tough
x = (9+25)/(2+15) = 34/17 = 2 y = (27-10)/(-15-2) = 17/-17 = -1 id say its right ;)
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