Question

p(x) = 2x^3-x^2-3x+1 (3) (-2)

Answer 1

If you are trying to find the value of the equation for 3 and for -2, then you would solve it the following way:

p(3)=2(3)^3-(3)^2-3(3)+1
p(3)=54-9-9+1
p(3)=37

p(-2)=2(-2)^3-(-2)^2-3(-2)+1
p(-2)=-16-4+6+1
p(-2)=-13