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if[1-tanx ][1-tanx]=2 then general value of tan x =???
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this looks more doable
:)
first lets solve \[(1-z)(1-z)=2\] \[1-2z+z^2=2\] \[z^2-2z-1=0\] \[z=1\pm\sqrt{2}\]so \[\tan(x)=1\pm\sqrt{2}\]
srry a mistake in question
if[1-tan \[\theta\]][1-tanx]=2 then general value of [x+\[\theta\]]=???
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if[1-tan θ][1-tanx]=2 then general value of [x+θ]=???
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