Question

(2p with a negative 1 exponent) cubed

Answer 1

\[\large (2p^{-1})^3\]


\[\large 2^3(p^{-1})^3\]


\[\large 2^3p^{-1*3}\]


\[\large 2^3p^{-3}\]


\[\large \frac{8}{p^{3}}\]

So \[\large (2p^{-1})^3=\frac{8}{p^{3}}\]