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n+3/5=(n-1)/2
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cross multiply
i got 3 2/3
thats right
cool thanks.,
\[\large \frac{n+3}{5}=\frac{n-1}{2}\] \[\large 2(n+3)=5(n-1)\] \[\large 2n+6=5n-5\] \[\large 2n=5n-5-6\] \[\large 2n-5n=-5-6\] \[\large -3n=-5-6\] \[\large -3n=-11\] \[\large n=\frac{-11}{-3}\] \[\large n=\frac{11}{3}\]
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no prblm yea 11/3= 3 2/3
btw, \[\large \frac{11}{3}=3\frac{2}{3}\]
thanks thanks
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