Question

Solve the equation at the given interval:
secx = -3, -π ≤ x < π
How on earth do you solve for this when its secant?

Answer 1

recall that
\[\sec(x)=\frac{1}{\cos(x)}\] and use that

Answer 2

\[\sec(x)=-3\iff \cos(x)=-\frac{1}{3}\]