Question

3x^3+5x^2-3x-5=0 factor by grouping.

Answer 1

\[x^2(3x+5)-1(3x+5)=0\]
\[(3x+5)(x^2-1)=0\]
\[3x+5=0,x^2-1=0\]
\[x=\frac{-5}{3},x=1\]

Answer 2

\[x^2-1=0\]
\[x=1,x=-1\]

Answer 3

sorry i forgot \[\pm\]

Answer 4

3x^3+5x^2-3x-5=0
3x^3-3x+5x^2-5=0
3x(x^2-1)+5(x^2-1)=0
(3x+5)(x^2-1)=0
(3x+5)(x+1)(x-1)=0