Question

Hey guys I need help. how do you do this question??
((4xy^2)^4/(5xy)^3)*(3x^2y)^2/(4xy^3)^2

Answer 1

(((4xy^(2))^(4))/((5xy)^(3)))*((3x^(2)y)^(2))/((4xy^(3))^(2))

Expand the exponent (4) to the expression.
((4^(4)x^(4)y^(2*4))/((5xy)^(3)))*((3x^(2)y)^(2))/((4xy^(3))^(2))

Multiply 2 by 4 to get 8.
((4^(4)x^(4)y^(8))/((5xy)^(3)))*((3x^(2)y)^(2))/((4xy^(3))^(2))

Raising a number to the 4th power is the same as multiplying the number by itself 4 times. In this case, 4 raised to the 4th power is 256.
((256x^(4)y^(8))/((5xy)^(3)))*((3x^(2)y)^(2))/((4xy^(3))^(2))

Expand the exponent (3) to the expression.
((256x^(4)y^(8))/(5^(3)x^(3)y^(3)))*((3x^(2)y)^(2))/((4xy^(3))^(2))

Cubing a number is the same as multiplying the number by itself 3 times (5*5*5). In this case, 5 cubed is 125.
((256x^(4)y^(8))/(125x^(3)y^(3)))*((3x^(2)y)^(2))/((4xy^(3))^(2))

Reduce the expression (256x^(4)y^(8))/(125x^(3)y^(3)) by removing a factor of x^(3)y^(3) from the numerator and denominator.
((256xy^(5))/(125))*((3x^(2)y)^(2))/((4xy^(3))^(2))

Expand the exponent (2) to the expression.
((256xy^(5))/(125))*(3^(2)x^(2*2)y^(2))/((4xy^(3))^(2))

Multiply 2 by 2 to get 4.
((256xy^(5))/(125))*(3^(2)x^(4)y^(2))/((4xy^(3))^(2))

Squaring a number is the same as multiplying the number by itself (3*3). In this case, 3 squared is 9.
((256xy^(5))/(125))*(9x^(4)y^(2))/((4xy^(3))^(2))

Expand the exponent (2) to the expression.
((256xy^(5))/(125))*(9x^(4)y^(2))/(4^(2)x^(2)y^(3*2))

Multiply 3 by 2 to get 6.
((256xy^(5))/(125))*(9x^(4)y^(2))/(4^(2)x^(2)y^(6))

Squaring a number is the same as multiplying the number by itself (4*4). In this case, 4 squared is 16.
((256xy^(5))/(125))*(9x^(4)y^(2))/(16x^(2)y^(6))

Reduce the expression (9x^(4)y^(2))/(16x^(2)y^(6)) by removing a factor of x^(2)y^(2) from the numerator and denominator.
((256xy^(5))/(125))*(9x^(2))/(16y^(4))

Reduce the expression by removing the common factor of 16y^(4) in the denominator of the first term (9x^(2))/(16y^(4)) and the numerator of the second term (256xy^(5))/(125).
9x^(2)*(16xy)/(125)

Multiply 9x^(2) by (16xy)/(125) to get (144x^(3)y)/(125).
(144x^(3)y)/(125)

Answer 2

good kush

Answer 3

thanks didi

Answer 4

welcome kush