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guys giv me general sormula sin 2x=cos 2x
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finally one we can do!
lol
we know \[2x=\frac{\pi}{4}\] or \[2x=\frac{5\pi}{4}\] etc that is \[2x=\frac{(2k+1)\pi}{4}\]
solve for x in one step and be happy we can actually get an answer
???
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i need general solution between 0<x<3\[\Pi\]/4
\[x=\frac{(2k+1)\pi}{8},x\in \mathbb Z\]
ooh i finally got the "zahl" right!
0<x<3Π/4
ur answer is wrong
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