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if 3^100-2^100 is divided by 11, what is the reminder can any1 explain
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i have an answer but it is not snappy so maybe there is a better way to do it
the answer is 0, i.e. 11 divides the number. it is because one of the factors of \[x^{100}-y^{100}\] is \[(x^4-x^3 y+x^2 y^2-x y^3+y^4) \] and if you replace x by 2 and y by 2 you get 55
Mathematica can handle unlimited precision numbers.\[\text{Mod}\left[3^{100}-2^{100},11\right]=0 \]
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