Question

SOLVE THE QUAD. EQUATON BY USING THE SQUARE ROOT PROPERTY
2X^2=32

Answer 1

\[\large 2x^2=32\]


\[\large x^2=\frac{32}{2}\]


\[\large x^2=16\]


\[\large x=\pm\sqrt{16}\]


\[\large x=\pm4\]

\[\large \text{So the solutions are } x=4 \ \text{ or } \ x = -4\]

Answer 2

x^2=16
then x=+4 or x=-4