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x ^{x}=x digits...Can u solve this...?
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x .log(x)=log(x) the answer is 1
1^[1]=1
\[x \ln(x)-\ln(x)=0\] \[\ln(x)[x-1]=0 \] \[\ln(x)=0=>x=1\] \[x-1=0=>x=1\]
you sure that is the only solution? it does not say \[x^x=x\]
it doesn't?
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i read it as \[x^x=x\text{ digits}\]
in my reading 8 would be a solution
did anyone solve the \[3^{100}-2^{100}\] divisible by 11 problem? i got an answer but i assume there is a snappier one
i wil see if i can find it
where exactly is this divisible by 11 problem?
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