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OpenStudy (anonymous):
NEGATIVE 5 RAISED TO ONE FIFTH POWER
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OpenStudy (zarkon):
\[\sqrt[5]{5}e^{\frac{2\pi i k}{5}-\frac{\pi}{5}i}\] \[\sqrt[5]{5}e^{\frac{\pi i (2k-1)}{5}}\]
OpenStudy (zarkon):
\[k\in\mathbb{Z}\]
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