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The area of a rectangular field is 875 m2.Two adjacent sides of the field are fenced with wood costing $5 per meter.The remaining two sides are fenced with steel costing $10/m.The total cost of the fencing is $900. What are the dimensions of the field?
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Let x be the length of the wood side, let y be the length of the steal side. xy=875 and 2x(5)+2y(10)=900. That's 10x+20y=900. Solve the first equation for one of the variables and plug it into the second.
Damnit. You got it first.
i have more dont worry im just really confused this is new to me im a ninth grader taking advanced algebra 2
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