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8x^3-27 how do you do it
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(2 x-3) (4 x^2+6 x+9)
\[(2x-3)^{3}\]
This is a standard formula, difference of cubes a^3-b^3 = (a-b)(a^2+ab+b^2)
thanks!
If what you're being asked to do is factor, then that's the answer. If you're being asked to solve it I can give you another method.
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I'm just being asked to factor
Ok then.
what about 24t^3+3 is it the same concept?
Essentially, yes. \[3(8t ^{3} +1)\] I could be mistaken though.
This is the sum of two perfect cubes (and a factor 3) There is a formula for that a^3 + b^3=(a+b)(a^2-ab+b^2)
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3(2t+1)((2t)^2-2t+1)
Might want to double check that.
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