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7x-1/x+4-1
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i need the answer in factored form
\[\large \frac{7x-1}{x+4}-1\] \[\large \frac{7x-1}{x+4}-1*(\frac{x+4}{x+4})\] \[\large \frac{7x-1}{x+4}-\frac{x+4}{x+4}\] \[\large \frac{7x-1-(x+4)}{x+4}\] \[\large \frac{7x-1-x-4}{x+4}\] \[\large \frac{6x-5}{x+4}\] So \[\large \frac{7x-1}{x+4}-1=\frac{6x-5}{x+4}\]
thank you so much!
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