Question

Checking my math!

(Problem to follow first post)

Answer 1

\[\frac{x^{2} - 4x - 21}{x^{2} - 16} \div \frac{x^{2} - 9}{x^{2} - 7x + 12}\]

\[\frac{x-7}{x+4}\]

Answer 2

The second part is my final answer, simplified after cancellation.

Answer 3

Steps:

\[\frac{(x-7)(x+3)}{(x-4)(x+4)} \div \frac{(x+3)(x-3)}{(x-4)(x-3)}\]

\[\frac{(x-7)}{(x+4)} * \frac{(x-3)}{(x-3)}\]

\[\frac{(x-7)}{(x+4)}\]

Answer 4

correct

Answer 5

Alright, thanks.