Question

Add
3x x
____ + _____
x^2 - 81 x-9

Answer 1

\[\large \frac{3x}{x^2-81}+\frac{x}{x-9}\]


\[\large \frac{3x}{(x-9)(x+9)}+\frac{x}{x-9}\]


\[\large \frac{3x}{(x-9)(x+9)}+\frac{x(x+9)}{(x-9)(x+9)}\]


\[\large \frac{3x}{(x-9)(x+9)}+\frac{x^2+9x}{(x-9)(x+9)}\]


\[\large \frac{3x+x^2+9x}{(x-9)(x+9)}\]


\[\large \frac{x^2+12x}{(x-9)(x+9)}\]


\[\large \frac{x^2+12x}{x^2-81}\]
So \[\large \frac{3x}{x^2-81}+\frac{x}{x-9}=\frac{x^2+12x}{x^2-81}\]