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lim x->0 (3/x^2+3x)-(1/x)?
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@raheen, i got -1/3. what did u get?
do u want me to draw it
\[^{} \lim_{x \rightarrow 0}[(3/(x^2+3x))-1/x]\] = -1/3
same as u mathballet
wait im gonna try to draw it
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no need to draw
|dw:1314779171591:dw|
REALLY bad drawing. i cant use the stupid equation editor thing
not bad, it still readable notations thank you
is that what u did to solve
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yes
i got 1/3 :/
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