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equation of tangent and normal of parabola y^2=16ax, at each ends of latus rectum
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latus rectum is aline that passes thru the focus; but id have to remember which line it is :)
its parallel to the directix so
f(x,y) = 16ax - y^2 df/dx = 16a df/dy = -2y the normal is a vector that matches: <16a,-2y> if i see it right
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